4(x+4)=3[x-(3-x)]

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Solution for 4(x+4)=3[x-(3-x)] equation: 


Simplifying
4(x + 4) = 3[x + -1(3 + -1x)]

Reorder the terms:
4(4 + x) = 3[x + -1(3 + -1x)]
(4 * 4 + x * 4) = 3[x + -1(3 + -1x)]
(16 + 4x) = 3[x + -1(3 + -1x)]
16 + 4x = 3[x + (3 * -1 + -1x * -1)]
16 + 4x = 3[x + (-3 + 1x)]

Reorder the terms:
16 + 4x = 3[-3 + x + 1x]

Combine like terms: x + 1x = 2x
16 + 4x = 3[-3 + 2x]
16 + 4x = [-3 * 3 + 2x * 3]
16 + 4x = [-9 + 6x]

Solving
16 + 4x = -9 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
16 + 4x + -6x = -9 + 6x + -6x

Combine like terms: 4x + -6x = -2x
16 + -2x = -9 + 6x + -6x

Combine like terms: 6x + -6x = 0
16 + -2x = -9 + 0
16 + -2x = -9

Add '-16' to each side of the equation.
16 + -16 + -2x = -9 + -16

Combine like terms: 16 + -16 = 0
0 + -2x = -9 + -16
-2x = -9 + -16

Combine like terms: -9 + -16 = -25
-2x = -25

Divide each side by '-2'.
x = 12.5

Simplifying
x = 12.5

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